![]() I tried pattern.split but did not work for me. String only has a matches() method (implemented equivalent to this code: pile(pattern).matcher(this). Some RE engines (modern ones) also allow you to write the first as \d (mnemonically: digit) and the second would then become. In Java Regex, there's a difference between Matcher.find() (find a match anywhere in the String) and Matcher.matches() (match the entire String). ![]() A better regex that would match only up to the closing bracket would be. In this example, we use a regular expression (regex) with Pattern.matcher() to check if the strings contain any numbers. (abc) (def) (123) as a single group rather than three separate groups. If your regular expression evaluator forces REs to be anchored, you need this.0-9. You want to match individual groups of letters / numbers in brackets, and the current regex will match only a single string of one or more such groups. How can I get the individual matches separately (like (aaa) alone and then (111) and so on). The regular expression you are looking for is simply this: 0-9 You do not mention what language you are using.How can I fix this regex and be able to match multiple groups?.I tried to use \ instead of \ but the regex gave different results than what I expected (it matches only one group like (aaa) not multiple groups like (aaa) (111) (ii). I always use the following regular expression to detect any kind of number in a string. You can download the Regex Cheat Sheet below. ![]() But when I use it in my code, the code does not compile. Regular expression Any number Ask Question Asked 12 years. In our Regular Expressions cheat sheet, we include essential Java classes and methods, Regex syntax, character classes, boundary matchers, logical operations, quantifiers, groups, backreferences, and pattern flags. I tested this regular expression on and it is working. To match one or more letters or numbers in parentheses one or more times. I am using the following regular expression I am using Java to process text using regular expressions. ![]()
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